12x^-34x^2+10x=0

Solution for 12x^-34x^2+10x=0 equation:

12x^-34x^2+10x=0

We add all the numbers together, and all the variables

-34x^2+22x=0

a = -34; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-34)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-34}=\frac{-44}{-68}
=11/17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-34}=\frac{0}{-68}
=0
$